Test Bank for College Physics, 4th Edition: Alan Giambattista
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Multiple Choice Questions
1. A 2.00 kg mass is located at (4.00 m, 0.00 m, 0.00 m) and a 4.00 kg mass is located at (0.00 m, 3.00 m, 0.00 m). If this system of masses rotated about the Z-axis perpendicular to the X-Y plane, then the moment of inertia of this system is
A. 50 kg m2 .
B. 55 kg m2
C. 58 kg m2 .
D. 62 kg m2
E. 68 kg m2 .
Section: 08.01 Rotational Kinetic Energy and Rotational Inertia
2. A 2.00 kg mass is located at (4.00 m, 0.00 m, 0.00 m) and a 4.00 kg mass is located at (0.00 m, 3.00 m, 0.00 m). If this system of masses rotated about the X-axis perpendicular to the Z-Y plane, then the moment of inertia of this system is
A. 23 kg m2
B. 28 kg m2 .
C. 33 kg m2
D. 36 kg m2 .
E. 41 kg m2 .
Section: 08.01 Rotational Kinetic Energy and Rotational Inertia
3. What is the rotational inertia of a solid iron disk of mass 41.0 kg with a thickness of 5.00 cm and radius of 30.0 cm, about an axis through the center and perpendicular to it?
A. 0.980 kg m2
B. 0.761 kg m2
C. 1.85 kg m2
D. 2.29 kg m2
Section: 08.01 Rotational Kinetic Energy and Rotational Inertia
4. A centrifuge has a rotational inertia of 5.50 10-3 kg m2. How much energy must be supplied to bring it from rest to 500 rad/s?
A. 627 J
B. 570 J
C. 688 J
D. 743 J
E. 583 J
Section: 08.01 Rotational Kinetic Energy and Rotational Inertia
5. A 4.00 kg mass is located at (2.00 m, 2.00 m, 0.00 m) and a 3.00 kg mass is located at (–1.0 m, 3.00 m, 0.00 m). If this system of masses rotated about the X-axis perpendicular to the Z-Y plane, then the moment of inertia of this system is
A. 24 kg m2 .
B. 36 kg m2
C. 43 kg m2 .
D. 56 kg m2 .
E. 62 kg m2 .
Section: 08.01 Rotational Kinetic Energy and Rotational Inertia
6. A 4.00 kg mass is located at (2.00 m, 2.00 m, 0.00 m) and a 3.00 kg mass is located at (
1 m, 3.00 m, 0.00 m). If this system of masses rotated about the Y-axis perpendicular to the X-Z plane, then the moment of inertia of this system is
A. 40 kg m2
B. 32 kg m2 .
C. 29 kg m2 .
D. 24 kg m2
E. 19 kg m2 .
Section: 08.01 Rotational Kinetic Energy and Rotational Inertia
7. A 6.00 kg mass is located at (2.00 m, 2.00 m, 2.00 m) and a 5.00 kg mass is located at (–1.0 m, 3.00 m, –2.00 m). If this system of masses rotated about the Z-axis perpendicular to the XY plane, then the moment of inertia of this system is
A. 60 kg m2
B. 79 kg m2 .
C. 85 kg m2
D. 98 kg m2 .
E. 112 kg m2
Section: 08.01 Rotational Kinetic Energy and Rotational Inertia
8. A 6.00 kg mass is located at (2.00 m, 2.00 m, 2.00 m) and a 5.00 kg mass is located at (–1.0 m, 3.00 m, –2.00 m). If this system of masses rotated about the X-axis perpendicular to the ZY plane, then the moment of inertia of this system is
A. 281 kg m2 .
B. 167 kg m2
C. 113 kg m2 .
D. 85 kg m2
E. 69 kg m2 .
Section: 08.01 Rotational Kinetic Energy and Rotational Inertia
9. A 6.00 kg mass is located at (2.00 m, 2.00 m, 2.00 m) and a 5.00 kg mass is located at (
1.0 m, 3.00 m, –2.00 m). If this system of masses rotated about the Y-axis perpendicular to the ZX plane, then the moment of inertia of this system is
A. 73 kg m2
B. 66 kg m2 .
C. 60 kg m2 .
D. 55 kg m2
E. 48 kg m2 .
Section: 08.01 Rotational Kinetic Energy and Rotational Inertia
10. The moment of inertia of a rod being rotated about one end is 1/3 ML2. What is the moment of inertia of a rod of length L and mass M being rotated about a point located 0.300 L?
A. 0.123 ML2
B. 0.198 ML2
C. 0.205 ML2
D. 0.240 ML2
E. 0.300 ML2
Section: 08.01 Rotational Kinetic Energy and Rotational Inertia
11. The moment of inertia of a rod being rotated about one end is 1/3 ML2. What is the moment of inertia of a rod of length L and mass M being rotated about a point located 0.40 L?
A. 0.080 ML2
B. 0.072 ML2
C. 0.068 ML2
D. 0.060 ML2
E. 0.056 ML2
Section: 08.01 Rotational Kinetic Energy and Rotational Inertia
12. A 20.0 cm wrench is used to generate a torque at a bolt. A force of 50 N is applied perpendicularly at the end of the wrench. The torque generated at the bolt is
A. 8.0 N•m.
B. 10 N•m.
C. 14 N•m.
D. 22 N•m.
E. 37 N•m.
Section: 08.02 Torque
13. A 30.0 cm wrench is used to generate a torque at a bolt. A force of 40 N is applied perpendicularly at the end of the wrench. The torque generated at the bolt is
A. 5.0 N•m.
B. 7.0 N•m.
C. 9.0 N•m.
D. 12 N•m.
E. 20 N•m.
Section: 08.02 Torque
14. A 20.0 cm wrench is used to generate a torque at a bolt. A force of 50 N is applied at the end of the wrench at an angle of 60.0 degrees to the wrench. The torque generated at the bolt is
A. 4.9 N•m.
B. 5.7 N•m.
C. 6.0 N•m.
D. 7.5 N•m.
E. 8.7 N•m.
Section: 08.02 Torque
15. A 30.0 cm wrench is used to generate a torque at a bolt. A force of 50.0 N is applied at the end of the wrench at an angle of 70.0 degrees. The torque generated at the bolt is
A. 10.4 N•m.
B. 14.1 N•m.
C. 19.7 N•m.
D. 21.5 N•m.
E. 26.2 N•m.
Section: 08.02 Torque
16. A torque of 20.0 N•m is applied to a bolt. The bolt rotates through an angle of 180 degrees. The work done in turning the bolt is
A. 72.5 J.
B. 51.9 J.
C. 62.8 J.
D. 49.9 J.
E. 58.4 J.
Section: 08.03 Work Done by a Torque
17. A torque of 15.0 N•m is applied to a bolt. The bolt rotates through an angle of 360 degrees. The work done in turning the bolt is
A. 94.2 J.
B. 91.3 J.
C. 96.7 J.
D. 89.9 J.
E. 98.1 J. Section: 08.03 Work Done by a Torque
18. A 2.00 kg mass is located at (4.00 m, 0.00 m, 0.00 m) and a 4.00 kg mass is located at (0.00 m, 3.00 m, 0.00 m). The center of gravity of the system of masses is
A. (1.33 m, 2.00 m, 0).
B. (1.33 m, 1.00 m, 0).
C. (1.50 m, 1.33 m, 0).
D. (2.00 m, 1.33 m, 0).
E. (1.33 m, 1.50 m, 0).
Section: 08.04 Equilibrium Revisited
19. A 5.00 kg mass is located at (2.00 m, 0.00 m, 0.00 m) and a 3.00 kg mass is located at (0.00 m, 4.00 m, 0.00 m). The center of gravity of the system of masses is
A. (1.25 m, 1.25 m, 0).
B. (1.50 m, 1.50 m, 0).
C. (1.25 m, 1.50 m, 0).
D. (1.50 m, 1.25 m, 0).
E. (1.00 m, 1.00 m, 0).
Section: 08.04 Equilibrium Revisited
20. A 5.00 kg mass is located at (2.00 m, 0.00 m, 3.00 m) and a 2.00 kg mass is located at (0.00 m, 4.00 m, –2.00 m). The center of gravity of the system of masses is
A. (10/7m, 8/7m, 11/7m).
B. (11/7m, 7/7m, 8/7m).
C. (7/7m, 10/7m, 11/7m).
D. (10/7m, 7/7m, 8/7m).
E. (8/7m, 7/7m, 10/7m).
Section: 08.04 Equilibrium
Revisited
21. A 5.00 kg mass is located at (1.0 m, 0.00 m, 3.00 m), a 2.00 kg mass is located at (0.00 m, 3.00 m, –2.00 m), and a 3.00 kg mass is located at (–1.0 m, –2.00 m , 0.00 m). The center of gravity of the system of masses is
A. (1/10m, 10/10m, 1/10m).
B. (2/10m, 0m, 11/10m).
C. (3/10m, 2/10m, 10/10m).
D. (10/10m, 2/10m, 3/10m).
E. (2/10m, 10/10m, 0m).
Section: 08.04 Equilibrium Revisited
22. A 6.00 kg mass is located at (1.0 m, –2.00 m, 3.00 m), a 5.00 kg mass is located at (1.0 m, 3.00 m, –2.00 m), and a 4.00 kg mass is located at (–1.0 m, –2.00 m, 2.00 m). The center of gravity of the system of masses is
A. (5/15m, -1/15m, 17/15m).
B. (5/15m, -17/15m, 5/15m).
C. (12/15m, -5/15m, 16/15m).
D. (7/15m, -5/15m, 16/15m).
E. (16/15m, -1/15m, 17/15m).
Section: 08.04 Equilibrium Revisited
23. Chris and Jamie are carrying Wayne on a horizontal stretcher. The uniform stretcher is 2.00 m long and weighs 100 N. Wayne weighs 800 N. Wayne's center of gravity is 75.0 cm from Chris. Chris and Jamie are at the ends of the stretcher. The force that Chris is exerting to support the stretcher, with Wayne on it, is
A. 250 N.
B. 350 N.
C. 400 N.
D. 550 N.
E. 650 N. Section: 08.04 Equilibrium Revisited
24. Chris and Jamie are carrying Wayne on a horizontal stretcher. The uniform stretcher is 2.00 m long and weighs 100 N. Wayne weighs 800 N. Wayne's center of gravity is 75.0 cm from Chris. Chris and Jamie are at the ends of the stretcher. The force that Jamie is exerting to support the stretcher, with Wayne on it, is
A. 250 N.
B. 300 N.
C. 350 N.
D. 400 N.
E. 550 N. Section: 08.04 Equilibrium Revisited
25. Jim and Mary are carrying Bob on a horizontal stretcher. The uniform stretcher is 2.00 m long and weighs 80 N. Bob weighs 600 N. Bob's center of gravity is 80 cm from Mary. Jim and Mary are at the ends of the stretcher. The force that Mary is exerting to support the stretcher, with Bob on it, is
A. 550 N.
B. 400 N.
C. 300 N.
D. 280 N.
E. 200 N. Section: 08.04 Equilibrium Revisited
26. Jim and Mary are carrying Bob on a horizontal stretcher. The uniform stretcher is 2.00 m long and weighs 80 N. Bob weighs 600 N. Bob's center of gravity is 80 cm from Mary. Jim and Mary are at the ends of the stretcher. The force that Jim is exerting to support the stretcher, with Bob on it, is
A. 280 N.
B. 320 N.
C. 380 N.
D. 400 N.
E. 520 N. Section: 08.04 Equilibrium Revisited
27. A 2.00 m long horizontal uniform beam of mass 20.0 kg is supported by a wire as shown in the figure. The wire makes an angle of 20.0 degrees with the beam. Attached to the beam 1.40 m from the wall is a ball with a mass of 40 kg. What is the tension in the string?
A. 1,000 N
B. 1,090 N
C. 2,100 N
D. 2,250 N
E. 2,680 N
Section: 08.04 Equilibrium Revisited
28. A 2.00 m long horizontal uniform beam of mass 20.00 kg is supported by a wire as shown in the figure. The wire makes an angle of 20.00 degrees with the beam. Attached to the beam 1.400 m from the wall is a ball with a mass of 40.00 kg. What are the vertical and horizontal components of the force of the wall on the beam at the hinge?
A. V = 175.6 N, H = 2,023 N
B. V = 186.6 N, H = 1,805 N
C. V = 195.4 N, H = 1,750 N
D. V = 200.6 N, H = 1,323 N
E. V = 215.6 N, H = 1,023 N
Section: 08.04 Equilibrium Revisited
29. A 1.500 m long uniform beam of mass 30.00 kg is supported by a wire as shown in the figure. The beam makes an angle of 10.00 degrees with the horizontal and the wire makes and angle of 30.00 degrees with the beam. A 50.00 kg mass, m, is attached to the end of the beam. What is the tension in the wire?
A. 2,034 N
B. 1,855 N
C. 1,435 N
D. 1,255 N
E. 1,035 N
Section: 08.04 Equilibrium Revisited
30. A 1.500 m long uniform beam of mass 30.00 kg is supported by a wire as shown in the figure. The beam makes an angle of 10.00 degrees with the horizontal and the wire makes and angle of 30.00 degrees with the beam. A 50.00 kg mass, m, is attached to the end of the beam. What are the vertical and horizontal components of the force of the wall on the beam at the hinge?
A. H = 1,458 N, V = 454.0 N
B. H = 1,300 N, V = 403.4 N
C. H = 1,179 N, V = 354.9 N
D. H = 979 N, V = 324.5 N
E. H = 750 N, V = 297.3 N
Section: 08.04 Equilibrium Revisited
31. A 75.0 kg ladder that is 3.00 m in length is placed against a wall at an angle theta. The center of gravity of the ladder is at a point 1.20 m from the base of the ladder. The coefficient of static friction at the base of the ladder is 0.800. There is no friction between the wall and the ladder. What is the vertical force of the ground on the ladder?
A. 625 N
B. 640 N
C. 735 N
D. 832 N
E. 900 N
Section: 08.04 Equilibrium Revisited
32. A 75.0 kg ladder that is 3.00 m in length is placed against a wall at an angle theta. The center of gravity of the ladder is at a point 1.20 m from the base of the ladder. The coefficient of static friction at the base of the ladder is 0.800. There is no friction between the wall and the ladder. What is the minimum angle the ladder makes with the horizontal for the ladder not to slip and fall?
A. 26.57 degrees
B. 30.34 degrees
C. 36.35 degrees
D. 40.55 degrees
E. 46.52 degrees
Section: 08.04
Equilibrium Revisited
33. A 75.0 kg ladder that is 3.00 m in length is placed against a wall at an angle theta. The center of gravity of the ladder is at a point 1.2 m from the base of the ladder. The coefficient of static friction at the base of the ladder is 0.400. There is no friction between the wall and the ladder. What is the minimum angle the ladder makes with the horizontal for the ladder not to slip and fall?
A. 35 degrees
B. 45 degrees
C. 53 degrees
D. 60 degrees
E. 65 degrees
Section: 08.04 Equilibrium Revisited
34. A 10 kg object has a moment of inertia of 1.25 kg m2. If a torque of 2.5 N•m is applied to the object, the angular acceleration is
A. 10 rad/s2 .
B. 8.0 rad/s2
C. 6.0 rad/s2 .
D. 4.0 rad/s2 .
E. 2.0 rad/s2 .
Section: 08.06 Rotational Form of Newtons Second Law
35. An 8.0 kg object has a moment of inertia of 1.00 kg m2. What torque is needed to give the object an angular acceleration of 1.5 rad/s2?
A. 3.0 N•m
B. 2.5 N•m
C. 2.0 N•m
D. 1.5 N•m
E. 1.0 N•m
36. A 10 kg sphere with a 25.0 cm radius has a moment of inertia of 2/5 MR2. If a torque of 2.0 N•m is applied to the object, the angular acceleration is
A. 1.0 rad/s2 .
B. 2.0 rad/s2
C. 4.0 rad/s2 .
D. 6.0 rad/s2 .
E. 8.0 rad/s2 .
Section: 08.06 Rotational Form of Newtons Second Law
37. An 8.00 kg object has a moment of inertia of 1.50 kg m2. If a torque of 2.00 N•m is applied to the object, the angular acceleration is
A. 0.750 rad/s2 .
B. 1.00 rad/s2
C. 1.33 rad/s2 .
D. 2.01 rad/s2
E. 2.67 rad/s2 .
Section: 08.06 Rotational Form of Newtons Second Law
38. A 5.00 kg object has a moment of inertia of 1.20 kg m2. What torque is needed to give the object an angular acceleration of 2.0 rad/s2?
A. 2.4 N•m
B. 2.6 N•m
C. 2.8 N•m
D. 3.0 N•m
E. 3.2 N•m
Section: 08.06 Rotational Form of Newtons Second Law
39. A 10 kg solid cylinder with a 50.0 cm radius has a moment of inertia of 1/2 MR2. If a torque of 2.0 N•m is applied to the object, the angular acceleration is
A. 1.0 rad/s2 .
B. 1.6 rad/s2
C. 1.8 rad/s2 .
D. 2.1 rad/s2 .
E. 2.3 rad/s2 .
Section: 08.06
Rotational Form of Newtons Second Law
40. A torque of 2.00 N•m is applied to a 10.0 kg object to give it an angular acceleration. If the angular acceleration is 1.75 rad/s2, then the moment of inertia is
A. 1.95 kg m2 .
B. 1.05 kg m2
C. 1.14 kg m2 .
D. 1.20 kg m2
E. 1.35 kg m2 .
Section: 08.06 Rotational Form of Newtons Second Law
41. A mass m1 is connected by a light string that passes over a pulley of mass M to a mass m2 sliding on a frictionless horizontal surface as shown in the figure. There is no slippage between the string and the pulley. The pulley has a radius of 25.0 cm and a moment of inertia of ½ MR2. If m1 is 1.00 kg, m2 is 2.00 kg, and M is 4.00 kg, then what is the acceleration of m1?
A. 1.55 m/s2
B. 1.96 m/s2
C. 2.06 m/s2
D. 2.33 m/s2
E. 2.72 m/s2
Section: 08.06 Rotational Form of Newtons Second Law
42. A mass m1 is connected by a light string that passes over a pulley of mass M to a mass m2 sliding on a frictionless horizontal surface as shown in the figure. There is no slippage between the string and the pulley. The pulley has a radius of 25.0 cm and a moment of inertia of ½ MR2. If m1 is 1.00 kg, m2 is 2.00 kg, and M is 4.00 kg, then what is the tension in the string attached to m1?
A. 6.83 N
B. 7.03 N
C. 7.84 N
D. 8.02 N
E. 8.33 N
Section: 08.06 Rotational Form of Newtons Second Law
43. A mass m1 is connected by a light string that passes over a pulley of mass M to a mass m2 sliding on a frictionless horizontal surface as shown in the figure. There is no slippage between the string and the pulley. The pulley has a radius of 25.0 cm and a moment of inertia of ½ MR2. If m1 is 1.00 kg, m2 is 2.00 kg, and M is 4.00 kg, then what is the tension in the string attached to m2?
A. 3.92 m/s2
B. 3.65 m/s2
C. 3.23 m/s2
D. 3.02 m/s2
E. 2.98 m/s2
Section: 08.06 Rotational Form of Newtons Second Law
44. A mass m1 is connected by a light string that passes over a pulley of mass M to a mass m2 sliding on a frictionless horizontal surface as shown in the figure. There is no slippage between the string and the pulley. The pulley has a radius of 25 cm and a moment of inertia of ½ MR2. If m1 is 4.00 kg, m2 is 2.00 kg, and M is 4.00 kg, then what is the acceleration of m1?
A. 4.9 m/s2
B. 4.5 m/s2
C. 4.1 m/s2
D. 3.9 m/s2
E. 3.7 m/s2
Section: 08.06 Rotational Form of Newtons Second Law
45. A mass m1 is connected by a light string that passes over a pulley of mass M to a mass m2 sliding on a frictionless horizontal surface as shown in the figure. There is no slippage between the string and the pulley. The pulley has a radius of 25.0 cm and a moment of inertia of ½ MR2. If m1 is 4.00 kg, m2 is 4.00 kg, and M is 4.00 kg, then what is the acceleration of m1?
A. 4.42 m/s2
B. 3.92 m/s2
C. 3.42 m/s2
D. 3.04 m/s2
E. 2.96 m/s2
Section: 08.06 Rotational Form of Newtons Second Law
46. A mass m1 is connected by a light string that passes over a pulley of mass M to a mass m2 sliding on a frictionless horizontal surface as shown in the figure. There is no slippage between the string and the pulley. The pulley has a radius of 25.0 cm and a moment of inertia of ½ MR2. If m1 is 4.00 kg, m2 is 4.00 kg, and M is 4.00 kg, then what is the tension in the string attached to m1?
A. 35.6 N
B. 32.7 N
C. 31.0 N
D. 29.0 N
E. 23.5 N
Section: 08.06 Rotational Form of Newtons Second Law
47. A mass m1 is connected by a light string that passes over a pulley of mass M to a mass m2 sliding on a frictionless horizontal surface as shown in the figure. There is no slippage between the string and the pulley. The pulley has a radius of 25.0 cm and a moment of inertia of ½ MR2. If m1 is 4.00 kg, m2 is 4.00 kg, and M is 4.00 kg, then what is the tension in the string attached to m2?
A. 10.4 N
B. 12.6 N
C. 15.7 N
D. 17.6 N
E. 19.8 N
Section: 08.06 Rotational Form of Newtons Second Law
48. A mass m1 is connected by a light string that passes over a pulley of mass M to a mass m2 as shown in the figure. Both masses move vertically and there is no slippage between the string and the pulley. The pulley has a radius of 30.0 cm and a moment of inertia of MR2. If m1 is 4.00 kg, m2 is 3.00 kg and M is 6.00 kg, then what is the acceleration of the masses?
A. 0.695 m/s2
B. 0.703 m/s2
C. 0.731 m/s2
D. 0.754 m/s2
E. 0.805 m/s2
Section: 08.06 Rotational Form of Newtons Second Law
49. A mass m1 is connected by a light string that passes over a pulley of mass M to a mass m2 as shown in the figure. Both masses move vertically and there is no slippage between the string and the pulley. The pulley has a radius of 30.0 cm and a moment of inertia of MR2. If m1 is 4.00 kg, m2 is 3.00 kg and M is 6.00 kg, then what is the tension in the string that is attached to m1?
A. 36.2 N
B. 44.6 N
C. 58.2 N
D. 60.6 N
E. 74.5 N
Section: 08.06 Rotational Form of Newtons Second Law
50. A mass m1 is connected by a light string that passes over a pulley of mass M to a mass m2 as shown in the figure. Both masses move vertically and there is no slippage between the string and the pulley. The pulley has a radius of 30.0 cm and a moment of inertia of MR2. If m1 is 4.00 kg, m2 is 3.00 kg and M is 6.00 kg, then what is the tension in the string that is attached to m2?
A. 20.7 N
B. 25.5 N
C. 31.7 N
D. 35.2 N
E. 41.3 N
Section: 08.06 Rotational Form of Newtons Second Law
51. A mass m1 is connected by a light string that passes over a pulley of mass M to a mass m2 as shown in the figure. Both masses move vertically and there is no slippage between the string and the pulley. The pulley has a radius of 20.0 cm and a moment of inertia of ½ MR2. If m1 is 3.00 kg, m2 is 6.00 kg and M is 4.00 kg, then what is the acceleration of the masses?
A. 5.05 m/s2
B. 4.75 m/s2
C. 4.05 m/s2
D. 3.44 m/s2
E. 2.67 m/s2
Section: 08.06 Rotational Form of Newtons Second Law
52. A mass m1 is connected by a light string that passes over a pulley of mass M to a mass m2 as shown in the figure. Both masses move vertically and there is no slippage between the string and the pulley. The pulley has a radius of 20.0 cm and a moment of inertia of ½ MR2. If m1 is 3.00 kg, m2 is 6.00 kg and M is 4.00 kg, then what is the tension in the string that is attached to mass m1?
A. 20.8 N
B. 27.4 N
C. 30.2 N
D. 37.4 N
E. 43.5 N
Section: 08.06 Rotational Form of Newtons Second Law
53. A mass m1 is connected by a light string that passes over a pulley of mass M to a mass m2 as shown in the figure. Both masses move vertically and there is no slippage between the string and the pulley. The pulley has a radius of 20.0 cm and a moment of inertia of ½ MR2. If m1 is 3.00 kg, m2 is 6.00 kg and M is 4.00 kg, then what is the tension in the string that is attached to mass m2?
A. 33.6 N
B. 42.8 N
C. 53.6 N
D. 63.4 N
E. 75.5 N
Section: 08.06 Rotational Form of Newtons Second Law
54. A mass m1 is connected by a light string that passes over a pulley of mass M to a mass m2 sliding on a frictionless incline as shown in the figure. There is no slippage between the string and the pulley. The pulley has a radius of 25.0 cm and a moment of inertia of ½ MR2. If m1 is 2.00 kg, m2 is 1.00 kg, M is 4.00 kg, and the angle is 60.0 degrees, then what is the acceleration of m1?
A. 3.98 m/s2 down
B. 3.27 m/s2 down
C. 3.15 m/s2 down
D. 2.94 m/s2 down
E. 1.64 m/s2 down
Section: 08.06 Rotational Form of Newtons Second Law
55. A mass m1 is connected by a light string that passes over a pulley of mass M to a mass m2 sliding on a frictionless incline as shown in the figure. There is no slippage between the string and the pulley. The pulley has a radius of 25.0 cm and a moment of inertia of ½ MR2. If m1 is 1.00 kg, m2 is 2.00 kg, M is 4.00 kg, and the angle is 60.0 degrees, then what is the acceleration of m1?
A. 0.00 m/s2
B. 1.20 m/s2
C. 1.80 m/s2
D. 2.20 m/s2
E. 2.80 m/s2
Section: 08.06 Rotational Form of Newtons Second Law
56. A mass m1 is connected by a light string that passes over a pulley of mass M to a mass m2 sliding on a frictionless incline as shown in the figure. There is no slippage between the string and the pulley. The pulley has a radius of 30.0 cm and a moment of inertia of MR2. If m1 is 4.00 kg, m2 is 4.00 kg, M is 4.00 kg, and the angle is 70.0 degrees, then what is the acceleration of m1?
A. 3.10 m/s2
B. 2.89 m/s2
C. 2.43 m/s2
D. 2.15 m/s2
E. 1.49 m/s2
Section: 08.06 Rotational Form of Newtons Second Law
57. A 4.00 kg solid sphere (I = 2/5 MR2) is spinning with an angular velocity of 23.0 rad/s. The diameter of the sphere is 20.0 cm. The angular kinetic energy of the spinning sphere is
A. 3.02 J.
B. 3.52 J.
C. 3.75 J.
D. 4.02 J.
E. 4.23 J.
Section: 08.06 Rotational Form of Newtons Second Law
58. A 20.0 kg hollow cylinder (I = MR2) has a diameter of 50.0 cm. The cylinder is rolling down a hill with a velocity of 5.00 m/s. The rotational kinetic energy of the rolling cylinder is
A. 225 J.
B. 200 J.
C. 175 J.
D. 150 J.
E. 250 J.
Section: 08.06 Rotational Form of Newtons Second Law
59. A 4.00 kg hollow sphere (I = 2/3 MR2) is spinning with an angular velocity of 10.0 rad/s. The diameter of the sphere is 20.0 cm. The angular kinetic energy of the spinning sphere is
A. 1.75 J.
B. 1.50 J.
C. 1.33 J.
D. 0.90 J.
E. 0.75 J.
Section: 08.06 Rotational Form of Newtons Second Law
60. A 4.00 kg hollow sphere of radius 5.00 cm starts from rest and rolls without slipping down a 30.0 degree incline. The acceleration of the center of mass of the hollow sphere is
A. 2.00 m/s2 .
B. 2.22 m/s2 .
C. 2.50 m/s2
D. 2.64 m/s2 .
E. 2.94 m/s2
Section: 08.07 The Motion of Rolling Objects
61. A 4.00 kg hollow sphere of radius 5.00 cm starts from rest and rolls without slipping down a 30.0 degree incline. If the length of the incline is 50.0 cm, then the velocity of the center of mass of the hollow sphere at the bottom of the incline is
A. 1.28 m/s.
B. 1.44 m/s.
C. 1.65 m/s.
D. 1.72 m/s.
E. 1.98 m/s.
Section: 08.07 The Motion of Rolling Objects
62. A 2.00 kg hollow sphere of radius 6.00 cm starts from rest and rolls without slipping down a 10.0 degree incline. If the length of the incline is 50.0 cm, then the velocity of the center of mass of the hollow sphere at the bottom of the incline is
A. 1.51 m/s.
B. 1.47 m/s.
C. 1.22 m/s.
D. 1.01 m/s.
E. 1.95 m/s.
Section: 08.07 The Motion of Rolling Objects
63. A 3.00 kg hollow sphere of radius 5.00 cm starts from rest and rolls without slipping down a 15.0 degree incline. If the length of the incline is 100 cm, then the velocity of the center of mass of the hollow sphere at the bottom of the incline is
A. 3.02 m/s.
B. 2.59 m/s.
C. 2.37 m/s.
D. 2.02 m/s.
E. 1.75 m/s.
Section: 08.07 The Motion of Rolling Objects
64. A 4.00 kg hollow cylinder of radius 5.00 cm starts from rest and rolls without slipping down a 30.0 degree incline. The acceleration of the center of mass of the cylinder is
A. 2.45 m/s2
B. 2.98 m/s2 .
C. 3.35 m/s2
D. 3.98 m/s2 .
E. 4.05 m/s2
Section: 08.07 The Motion of Rolling Objects
65. A 4.00 kg hollow cylinder of radius 5.00 cm starts from rest and rolls without slipping down a 30.0 degree incline. If the length of the incline is 50.0 cm, then the velocity of the center of mass of the cylinder at the bottom of the incline is
A. 1.35 m/s.
B. 1.82 m/s.
C. 1.57 m/s.
D. 2.55 m/s.
E. 3.02 m/s.
Section: 08.07 The Motion of Rolling Objects
66. A 4.00 kg solid sphere of radius 5.00 cm starts from rest and rolls without slipping down a 30.0 degree incline. The acceleration of the center of mass of the solid sphere is
A. 1.50 m/s2 .
B. 2.00 m/s2
C. 2.50 m/s2 .
D. 3.00 m/s2
E. 3.50 m/s2 .
Section: 08.07 The Motion of Rolling Objects
67. A 4.00 kg solid sphere of radius 5.00 cm starts from rest and rolls without slipping down a 30.0 degree incline. If the length of the incline is 50.0 cm, then the velocity of the center of mass of the solid sphere at the bottom of the incline is
A. 1.69 m/s.
B. 1.87 m/s.
C. 2.33 m/s.
D. 2.75 m/s.
E. 3.22 m/s.
Section: 08.07 The Motion of Rolling Objects
68. A 100 kg solid spherical rock (I = 2/5 MR2) has a diameter of 50.0 cm. The rock is rolling down a hill with a velocity of 5.00 m/s. The total kinetic energy (angular + translational) of the rolling rock is
A. 1,750 J.
B. 2,000 J.
C. 2,250 J.
D. 2,670 J.
E. 2,900 J.
Section: 08.07 The Motion of Rolling Objects
69. A 2.00 kg solid sphere (I = 2/5 MR2) with a diameter of 50.0 cm is rotating at an angular velocity of 5.0 rad/s. The angular momentum of the rotating sphere is
A. 0.55 kg m2/s.
B. 0.48 kg m2/s.
C. 0.37 kg m2/s.
D. 0.25 kg m2/s.
E. 0.20 kg m2/s.
Section: 08.08 Angular Momentum
70. An ice dancer with her arms stretched out starts into a spin with an angular velocity of 1.00 rad/s. Her moment of inertia with her arms stretched out is 2.48 kg m2. What is her angular velocity when she pulls in her arms to make her moment of inertia 1.40 kg m2?
A. 2.67 rad/s
B. 2.45 rad/s
C. 2.03 rad/s
D. 1.90 rad/s
E. 1.77 rad/s
Section: 08.08 Angular Momentum
71. An ice dancer with her arms stretched out starts into a spin with an angular velocity of 1.00 rad/s. Her moment of inertia with her arms stretched out is 2.48 kg m2. What is the increase in her rotational kinetic energy when she pulls in her arms to make her moment of inertia 1.40 kg m2?
A. 0.957 J
B. 0.902 J
C. 0.870 J
D. 0.750 J
E. 0.690 J
Section: 08.08 Angular Momentum
72. A grinding wheel has a mass of 250 kg and moment of inertia of 500 kg m2. A torque of 100 N•m is applied to the grinding wheel. If the wheel starts from rest, what is the angular momentum of the wheel after 5.0 seconds?
A. 650 kg m2/s
B. 500 kg m2/s
C. 450 kg m2/s
D. 300 kg m2/s
E. 250 kg m2/s
Section: 08.08 Angular Momentum
73. A 10 kg solid cylinder (I = 1/2 MR2) with a radius of 30.0 cm is rotating about a vertical axis through its center. If the angular momentum is increasing at the rate of 25 kg m2/s, then what is the torque?
A. 70 N•m
B. 45 N•m
C. 37 N•m
D. 25 N•m
E. 12 N•m
Section: 08.08 Angular Momentum
74. A 10 kg solid cylinder (I = 1/2 MR2) with a radius of 30.0 cm is rotating about a vertical axis through its center. If the angular momentum is increasing at the rate of 25.0 kg m2/s, then what is the angular acceleration?
A. 75.3 rad/s2
B. 65.9 rad/s2
C. 55.6 rad/s2
D. 40.5 rad/s2
E. 35.2 rad/s2 Section: 08.08 Angular Momentum
75. A pirate demands that his 75kg prisoner “walk the plank”. The prisoner walks out on an 8.0m long, 50kg horizontal board that juts out from the side of the pirate ship. If he walks out 7.5m from the place where the board is connected to the ship’s side, what is the net torque applied to the board?
A. 5500 Nm
B. 7500Nm
C. 0 Nm
D. 2000 Nm
E. Cannot determine Section: 08.02 Torque
76. A pole-vaulter holds out a 5.5kg, 4.75m pole horizontally in front of him. Assuming the pole is uniform in construction, and that he holds the pole with one hand at the very end, and one hand 0.75m from the end, what is the torque applied by the Earth to the pole?
A. 40N
B. 88N
C. Not enough information is given
D. 128N Section: 08.02 Torque
77. A 1.5m long dowel (a cylindrical rod) is pivoted about the end so that it is a pendulum of sorts - it can freely swing in a vertical plane. The dowel has a diameter of 2.0cm, and its density is 3.2 g/cm3 . When it is positioned in its swing such that its angle with the vertical is 22.5 degrees, what is the torque on the rod about the pivot due to its weight?
A. 17Nm
B. 42Nm
C. 11Nm
D. 10Nm
E. 44Nm
F. 41 Nm
Section: 08.02 Torque
78. A 1.5m long dowel is pivoted about the end so that it is a pendulum of sorts - it can freely swing in a vertical plane. At the other end of the dowel is a brass weight having mass 1.5kg. (The center of the brass weight is 1.5m from the pivot point. When the rod is positioned in its swing such that its angle with the vertical is 22.5 degrees, what is the torque on the rod about the pivot due to the presence of the brass weight?
A. 8.4Nm
B. 22 Nm
C. 20 Nm
D. 9.1 Nm
Section: 08.02 Torque
79. A 1.5m long, 0.75kg dowel is pivoted about the end so that it is a pendulum of sorts - it can freely swing in a vertical plane. At the other end of the dowel is a brass weight having mass 1.5kg. (The center of the brass weight is 1.5m from the pivot point. When the rod is positioned in its swing such that its angle with the vertical is 22.5 degrees, what is the net torque on the rod about the pivot?
A. 11 Nm
B. 28 Nm
C. 9.5 Nm
D. 25 Nm Section: 08.02 Torque
80. A piston in an internal combustion engine applies torque during 150o of each full rotation of the crankshaft to which it is connected. Suppose an 8-cylinder engine (8 such pistons) is running with its crankshaft turning at 2500rpm and produces 410J of work each second. What is the torque applied to the crank shaft by one of the engine’s eight pistons?
A. 3.8 Nm
B. 1.6 Nm
C. 0.47Nm
D. 0.20 Nm
Section: 08:03 Calculating Work Done from the Torque
81. A fire fighter tightens the nut on the top of a fire hydrant using a large wrench. If she applies a force of 250N perpendicular to the wrench, at a point 0.75m from the axis of rotation of the nut, how much work does she do on the nut as she rotates it through 45o?
A. 190 J
B. 150 J
C. 290 J
D. 130 J
Section: 08:03 Calculating Work Done from the Torque
82. A propeller is spun up from rest to 1500 rpm under the influence of a constant torque in 15.0s. If the work done by the engine in giving the propeller its final angular velocity is 25kJ, what is the torque supplied by the engine?
A. 21Nm
B. 11 Nm
C. 42 Nm
D. 21 Nm
E. 130 Nm
Section: 08:03
Calculating Work Done from the Torque
83. A 55kg girl swings on a swing, whose seat is attached to the pivot by 2.5m long rigid rods (considered to be massless in this problem). As she swings, she rises to a maximum height such that the angle of the rods with respect to the vertical is 32 degrees. What is the average torque on the rods due to her weight, as she moves during one cycle of her swinging from the bottom of her swing path to the highest point?
A. 370 Nm
B. 970 Nm
C. 2400 Nm
D. 2000 Nm
Section: 08:03
Calculating Work Done from the Torque
84. A brake pad is used to give a normal force of 150N to the outer surface of a 0.25kg spinning disk, in order to slow it down from 250rpm to rest. The disk’s radius is 0.25m. If the coefficient of friction between the pad and the disk is 0.45, how much time was required for the disk to slow from 250 rpm to rest?
A. 0.19s
B. 0.55s
C. 2.4s
D. 12s Section: 08:03
Calculating Work Done from the Torque
85. A pole-vaulter holds out a 4.75m pole horizontally in front of him. Assuming the pole is uniform in construction, and that he holds the pole with one hand at the very end, and one hand 0.75m from the end, what is the ratio of the force applied by the hand on the end of the pole to the weight of the pole?
A. 3.2
B. 2.7
C. 5.3
D. 2.2 Section: 08.04 Rotational Equilibrium
86. An auto mechanic is attempting to loosen a bolt in an engine using a large wrench, but to no avail. If she applies a force of 510N perpendicular to the wrench she is using, applied at 0.75m from the axis of rotation of the bolt, what is the value of the friction force applied to the outer surface of the bolt’s threads? The threaded portion of the bolt has diameter 1.2cm.
A. 3.2 kN
B. 510N
C. 32kN
D. 1.6kN
E. 16kN Section: 08.04 Rotational Equilibrium
87. A 0.50kg disk spins at 250rpm. A torque of 12.5Nm is applied for 0.150s to bring it to rest. What is the disk’s radius?
A. 0.54m
B. 0.38m
C. 0.29m
D. 0.14m Section: 08.08 Angular Momentum
88. An irregularly shaped object is attached to an axle so that it may be spun. If a torque of 250Nm must be applied for 1.25s in order to give it a rotation period of 0.10s, what is its moment of inertia?
A. 5.0kgm2
B. 31kgm2
C. 4.0kgm2
D. 25kgm2
Section: 08.08 Angular Momentum
89. A 25.0kg propeller may be considered a 4.5m-long rod spun about its center. What final angular velocity does the propeller have if a torque of 1100Nm is applied for 1.2s?
A. 31 rad/s
B. 26 rad/s
C. 7.8 rad/s
D. 2.6 rad/s
Section: 08.08 Angular Momentum
90. A system in equilibrium cannot have
A. any forces on it
B. a non-zero velocity
C. any torques on it
D. a non-zero acceleration
Section: 08.04 Rotational Equilibrium
91. The rotational kinetic energy of which of the following objects is greatest? Each has mass M and radius R and rotates with angular velocity
A. all have the same rotational KE
B. a solid sphere
C. a solid cylinder
D. a thin-walled spherical shell
E. a thin-walled cylindrical shell
Section: 08.06 Rotational Form of Newtons Second Law
92. A thin rod is pivoted around its end, and an identical rod around its center. If they are to have the same rotational kinetic energy, then end/center =
A. 2
B. 1
C. 1/2
D. 1/4
E. 4
Section: 08.06 Rotational Form of Newtons Second Law